1.

If |{:(0,sinalpha,sinbeta),(sinalpha,0,singamma),(sinbeta,singamma,0):}|=|{:(1,sinalpha,sinbeta),(sinalpha,1,singamma),(sinbeta,singamma,1):}| then

Answer»

`sinalpha.sinbeta,singamma=1`
`sinalpha+sinbeta+singamma=1`
`SIN^(2)alpha+sin^(2)beta+sin^(2)gamma=1`
0

Answer :C


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