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If `1/(1^2)+1/(2^2)+1/(3^2)+ tooo=(pi^2)/6,t h e n1/(1^2)+1/(3^2)+1/(5^2)+`equals`pi^2//8`b. `pi^2//12`c. `pi^2//3`d. `pi^2//2`A. `pi^2//8`B. `pi^2//8`C. `pi//3`D. `pi^2//2`

Answer» Correct Answer - A
`1/1^(2)+1/3^(2)+1/5^(2)+1/7^(2)+..`
`=(1/1^(2)+1/2^(2)+1/3^(2)+1/4^(2)+1/5^(2)+1/6^(2)+1/7^(2)+..)`
`-(1/2^(2)+1/4^(2)+1/6^(2)+..)`
`=pi^(2)/6-1/4(1/1^(2)+1/2^(2)+1/3^(2)+..)`
`=pi^(2)/6-1/4(pi^(2)/6)`
`=pi^(2)/8`


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