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If 1/6 sintheta, costheta and tantheta are in G.P. then the general solution for theta is- |
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Answer» `2npi+-pi/3` `RARR COS^(2)theta=1/6(sintheta.tantheta) rArr 6cos^(3)theta+cos^(2)theta-1=0` `therefore (2costheta-1)(3 cos^(2)theta+2costheta+1)=0` `rArr costheta=1/2` (other VALUES of `costheta` are imaginary) `rArr costheta=cospi/3 rArr theta=2npi+-pi/3, N in I`. |
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