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If `1/6 sintheta, costheta` and `tantheta` are in G.P. then the general solution for `theta` is-A. `2npi+-pi/3`B. `2npi+-pi/6`C. `npi+-pi/3`D. none of these |
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Answer» Correct Answer - a Since, `1/6sintheta,costheta, tantheta` are in G.P. `rArr cos^(2)theta=1/6(sintheta.tantheta) rArr 6cos^(3)theta+cos^(2)theta-1=0` `therefore (2costheta-1)(3 cos^(2)theta+2costheta+1)=0` `rArr costheta=1/2` (other values of `costheta` are imaginary) `rArr costheta=cospi/3 rArr theta=2npi+-pi/3, n in I`. |
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