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If `1/(b-a)+1/(b-c)=1/a+1/c ,`then`a ,b ,a n dc`are in H.P.`a ,b ,a n dc`are in A.P.`b=a+c``3a=b+c`A. a,b, and c are in H.PB. a,b, and c are in A.PC. b=a+cD. 3a= b+c |
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Answer» Correct Answer - A::B `1/(b-a)+1/(b-c)=1/a+1/c` or `1/(b-a)-1/c=1/a-1/(b-c)` or `(c-b+a)/(c(b-a))=(b-c-a)/(a(b-c))` `rArrc-b+a=0` or `1/(c(b-a))=1/(a(c-b))` `rArrb=a+c` or bc-ac=ac-ab `rArrb=a+c`or `b=(2ac)/(a+c)` |
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