1.

If 1 mL of water contains 20 drops, then number of molecules in a drop of water is

Answer»

`6.023xx10^(23)`
`1.376xx10^(26)`
`1.6673xx10^(21)`
`4.346xx10^(20)`

Solution :1 ML of WATER = 1 g of water `(d_(H_(2)O)="1 g mL"^(-1))`
`therefore" 20 drops of "H_(2)O=1 g`
`therefore" 1 drop of "H_(2)O=(1)/(20)g=0.05g`
`=(0.05)/(18)"mole"=(0.05)/(18)xx6.022xx10^(23)" molecules"`
`=1.673xx10^(21)` molecules.


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