1.

if (1+tan`alpha`)(1+tan4`alpha`) =2 where `alpha` `in` (0 , `pi/16`) then `alpha ` equal toA. `(pi)/(20)`B. `(pi)/(30)`C. `(pi)/(40)`D. `(pi)/(60)`

Answer» Correct Answer - A
`(1+tanA)(1+tanB)=2`
`rArr tan A+tan B=1-tan A tan B`
`rARr tan(A+B)=1,i.e, A+B=(pi)/(4)`
or `alpha+4alpha=(pi)/(4)` i.e. `alpha=(pi)/(20)`


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