InterviewSolution
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InterviewSolution
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If `(1-tan theta)(1+tan theta)sec^2 theta+2^(tan^2 theta)=0` then in the interval `(-pi/2,pi/2),` the value of `theta` is |
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Answer» Given that `(1-tan theta) (1+tan theta) sec^(2) theta+2^(tan^(2) theta)=0` or `(1- tan^(2) theta) (1+tan^(2) theta)+2^(tan^(2) theta)=0` Let us put `tan^(2) theta=t`. Then `(1-t) (1+t)+2^(t)=0" "or" "1-t^(2)+2^(t)=0` It is clearly satisfied by `t=3`. thus, we get `tan^(2) theta=3` Therefore, `theta= pm pi//3` in the given interval. |
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