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If `(1+x-2x^2)^6=1+a_1x+a_2x^(12)++a_(12)x^(12),`then find the value of `a_2+a_4+a_6++a_(12)dot` |
Answer» Correct Answer - 31 `(1+x-2x^(2))^(6) = 1+a_(1)x+a_(2)x^(2)+"…."+a_(12)x^(12)` Putting `x = 1` and `x = - 1` and adding the results, we get `64 = 2(1+a_(2)+a_(4)+"….")` `:. a_(2)+a_(4)+a_(6)+"…."a_(12) = 31` |
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