1.

If 10^(21) molecules are removed from 100mg CO_(2). Then number of moles of CO_(2) left are:

Answer»

`6.10xx10^(-4)`
`2.8xx10^(-3)`
`2.28xx10^(-3)`
`1.36xx10^(-2)`

Solution :Number of molecules in 100 mg `CO_(2)`
`=("Mass ")/("Molar mass")xx6.023xx10^(23)`
`=(0.1)/(44)xx6.023xx10^(23)`
`=1.368xx10^(21)`
Molecules REMAINING `=1.368xx10^(21)-10^(21)=0.368xx10^(21)`
Number of moles remaining `=(0.368xx10^(21))/(6.023)xx10^(23)=6.1xx10^(-4)`


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