1.

If 10^(21) molecules are removed from 200 mg of CO_(2), then the number of moles of CO_(2), then the number of moles of CO_(2) left are

Answer»

`2.88xx10^(-3)`
`1.66xx10^(-3)`
`4.54xx10^(-3)`
`1.66xx10^(-2)`

Solution :200 mg of `CO_(2)=0.200g=(0.2)/(44)mol`
`=(0.2)/(44)xx6.023xx10^(23)` molecules
After removing `10^(21)` molecules, molecules left
`=(2.738-1)10^(21)=1.738xx10^(21)` molecules
`=(1.738xx10^(21))/(6.022xx10^(23))mol=2.88xx10^(-3)mol.`


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