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If 10^(9) electrons move out of a body to another body every second, how much time is required to get a total charge of 1 C on the other body ? |
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Answer» Solution :If no. of electrons TRANSFERRED from first body to second body in UNIT TIME is `N/t` then total CHARGE transferred in t. time will be, `Q(N/t) xx t. xx e` `therefore 1 = 10^(9) xx t. xx 1.6 xx 10^(-19)` `therefore t. =1/(1.6 xx 10^(-10)) = 10^(10)/1.6s` `therefore t. = 198.2` year |
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