If 100 calorie of heat are added to the same system as in example 1 and a work of 50 calorie is done on the system, calculate the energy change of the system.

If 100 calorie of heat are added to the same system as in example 1 an

1.	If 100 calorie of heat are added to the same system as in example 1 and a work of 50 calorie is done on the system, calculate the energy change of the system.
Answer» Heat absorbed q=100cal Work done on the system, `w=+50cal` ltBrgt Applying the first law of thermodynamics, `DeltaD=q+w=(100+50)=150`calorie In the above examples, the final state is same but the paths adopted are different. Thus, the change in energy of the system depends onthe intial and finial states but does not depend on the path by which the final state has reached, q and w are, therefore, not state functions but `DeltaU` is a state functions.

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If 100 calorie of heat are added to the same system as in example 1 and a work of 50 calorie is done on the system, calculate the energy change of the system.

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