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If 100 ml of 1.0 M NaOH solution is diluted to 1.0 L, the resulting solution contains |
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Answer» 1.0 mol of NaOH `1.0xx100=M_(2)xx1000` or `M_(2)=(1.0xx100)/(1000)=0.1` `:. 0.1` MOLE of NaOH is PRESENT in 1.0 L solution. |
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