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If 10,000V applied across an X-ray tube, what will be the ratio of de Broglie wavelength of the incident electrons to the shortest wavelength of X-ray produced (elm of electron is 1.7xx10^(11) C/Kg) |
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Answer» Solution :De Broglie wave LENGTH of incident electron is `lamda_(1)=(h)/(sqrt(2meV))""......(1)` SHORTEST wavelength of X ray photon is `lamda_(2)=(hc)/(Ve)""......(2)` `implies(lamda_(1))/(lamda_(2))=(1)/(c)sqrt(((V)/(2))((e)/(m)))=0.1` |
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