If 102y = 25, then 10-y equalsA, \(-\frac{1}5\)B.\(\frac{1}{50}\)C.\(

1.	If 102y = 25, then 10-y equalsA, \(-\frac{1}5\)B.\(\frac{1}{50}\)C.\(\frac{1}{625}\)D.\(\frac{1}5\)
Answer» 10^2y = 25 = 10^y = x = x² = 5² = x = 5 = 1/x = 10^-y = 1/5

If 102y = 25, then 10-y equalsA, \(-\frac{1}5\)B.\(\frac{1}{50}\)C.\(\frac{1}{625}\)D.\(\frac{1}5\)

Answer»

10^2y = 25

= 10^y = x

= x² = 5²

= x = 5

= 1/x = 10^-y

= 1/5