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If `13.6 eV` energy is required to ionized the hydrogen atom then the energy required to ionize the hydrogen atom , then the energy required to remove an electron from `n = 2 ` isA. `10.2 eV`B. `0 eV`C. `3.4 eV`D. `6.8 eV` |
Answer» Correct Answer - C Energy required to lonize a atom from `n^(th)` orbit is `= +13.6/n^(2) eV` `E_(2)=(+13.6)/2^(2) eV= +3.4 eV` |
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