1.

If 18g of glucose (C_(6)H_(12)O_(6)) is present in 1018 g of an aqueous solution of glucose, it is said to be

Answer»

1 MOLAL
1.1 molal
0.5 molal
0.1 molal

Solution :18 g glucose `=18/180 ` mol =0.1 mol.
As it is present in (1018-18) = 1000 g WATER, the solution is 0.1 molal.


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