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If `[2-1 1 0-3 4]A=[-1-8-10 1-2-5 9 22 15]`, then sum of all the elements of matrix `A`is`0`b. `1`c. `2`d. `-3` |
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Answer» Correct Answer - B Since the product matrix is `3xx3` matrix and the pre-multiplier of a is a `3xx2` matrix, therefore A is `2xx3` matrix. Let `A=[(l,m,n),(x,y,z)]`. Then the given equation becomes `[(2,-1),(1,0),(-3,4)][(l,m,n),(x,y,z)]=[(-1,-8,-10),(1,-2,-5),(9,22,15)]` or `[(2l-x,2m-y,2n-z),(l,m,x),(-3l+4x,-3m+4y,-3n+4z)]=[(-1,-8,-10),(1,-2,-5),(9,22,15)]` or `2l-x=-1, 2m-y=-8, 2n -z=-10`, `l=1, m=-2, n=-5` `implies x=3, y=4, z=0, l=1, m=-2, n=-5` `implies A=[(l,m,n),(x,y,z)]=[(1,-2,-5),(3,4,0)]` |
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