1.

If 2.2 kW of power having 22000 V is transmitted on a transmission line with 10Omega resistance then power dissipated in the form of thermal energy will be ……

Answer»

0.1 W
1 W
10 W
100 W

Solution :`P=2.2xx10^3` W, V=22000 V, R=`10Omega`
P=VI
`therefore I=P/V=2200/22000`=0.1 A
Power CONSUMED in FORM of THERMAL energy
`=I^2R=0.01 xx 10`
=0.1 W


Discussion

No Comment Found

Related InterviewSolutions