1.

If 2÷3 i a root of the equation k x∧2-x-2 =0 , then find the value of 'k'

Answer»

if 2/3 is ROOT of EQUATION

we can substitute the VALUE of x

k(2/3)²-(2/3)-2=0

4k/9-2/3-2=0

(4k-6-18)/9=0

4k-24=0

k=24/6

k=4

hence K = 4



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