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If 2÷3 i a root of the equation k x∧2-x-2 =0 , then find the value of 'k' |
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Answer» we can substitute the VALUE of x k(2/3)²-(2/3)-2=0 4k/9-2/3-2=0 (4k-6-18)/9=0 4k-24=0 k=24/6 k=4 hence K = 4 |
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