If `(2.3)^x=(0.23)^y=1000` then find the value of `x` and `y`. – InterviewSolution

InterviewSolution

1.	If `(2.3)^x=(0.23)^y=1000` then find the value of `x` and `y`.
Answer» `(2.3)^x=1000` Take log on both side `log_10(2.3)^x=log_10(1000)` `xlog_10(2.3)=3log_10 10=3` `x=3/(log2.3)` `(0.23)^y=1000` Take log both side `ylog(0.23)=log1000` `y=3/(log(0.23))`.

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