InterviewSolution
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InterviewSolution
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If `2[{:(3,4),(5,x):}]+[{:(1,y),(0,1):}]=[{:(7,0),(10,5):}]`, find (x-y). |
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Answer» We have `2[{:(3,4),(5,x):}]+[{:(1,y),(0,1):}]=[{:(7,0),(10,5):}]` `implies" "[{:(6,8),(10,2x):}]+[{:(1,y),(0,1):}]=[{:(7,0),(10,5):}]` `implies" "[{:(6+1,8+y),(10+0,2x+1):}]=[{:(7,0),(10,5):}]` `implies" "2x+1=5" and "8+y=0` [comparing the corresponding elements] `implies" "x=2" and "y=-8.` `implies" "(x-y)=2-(-8)=10.` |
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