1.

If 2.7 gm aluminum metal is deposited on electrodes when two different electrolytic cell having molten Cu(NO_(3))_(2) and Al(NO_(3))_(3) respectively are arranged in series, then how much copper metal is produced ? (Cu=63.5,Al=27.0" gm "mol^(-1)).

Answer»

9.525 gm
31.75 gm
63.5 gm
190.5 gm

Solution :`AL^(3+)+3e^(-) to Al`
So, 3 F electricity GIVES 27 gm of Al, but Al is produced only 2.7 gm
So, FARADAY `=(2.7)/(27)xx3=0.3` Faraday
Reaction : `Cu^(2+)+2E^(-) to Cu`
So 2 F electricity gives 63.5 gm of Cu
So, 0.3 F electricity gives `=(0.3xx63.5)/(2)`
`=9.525gm` Cu


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