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If 2 and -2 are zeroes of the polynomial p(x) = ax4+2x3 -3x2 + bx -4, find the value of a and b |
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Answer» a=3/2 and b=-4Step-by-step EXPLANATION:x=2ax^4+2x^3 -3x^2 + BX -4=0 => 16a+16-12+2b-4=0 =>16a+2b=168a+b=8 ------>(1)x=-2ax^4+2x^3 -3x^2 + bx -4=0 => 16a-16-12-2b-4=0 => 16a-2b=328a-b=16 ------>(2)Combining (1) and (2) we FIND values of a and b:16a=24=> a=3/2 and b=-4 |
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