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If `2 sin^(2) ((pi//2) cos^(2) x)=1-cos (pi sin 2x), x ne (2n + 1) pi//2, n in I`, then `cos 2x` is equal toA. `1//5`B. `3//5`C. `4//5`D. `1` |
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Answer» Correct Answer - B The given equation is equivalent to `2 sin^(2) ((pi//2) cos^(2) x)=2 sin^(2) ((pi//2) sin 2x)` or `cos^(2) x= sin 2x` or `cos x (cos x -2 sin x)=0` `rArr 1-2 tan x=0` as `cos x ne0, x ne (2n+1) pi/2` or `tan x=1/2` `rArr cos 2x=(1-tan^(2) x)/(1+tan^(2) x)=3/5` |
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