If "20.0 g mL"^(-1) of "1.0 M CaCl"_(2) and "60.0 cm"^(3) of "0.20 M C – InterviewSolution

1.	If "20.0 g mL"^(-1) of "1.0 M CaCl"_(2) and "60.0 cm"^(3) of "0.20 M CaCl"_(2) are mixed, what will be the molarity of the final solution?
Answer» SOLUTION :`M_(1)V_(1)+M_(2)V_(2)=M_(3)V_(3)" ,"1xx20 +0.2 xx60=M_(3)(20+60)or M_(3)=(32)/(80)=0.40M`

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