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If 20 ml of 0.25N strong acid and 30 ml of 0.2 N of strong base are mixed, then the resulting solution is

Answer»

0.25 N basic
0.2 N acidic
0.25 N acidic
0.2 N basic

Solution :`V_(1)=20ML,N_(1)=0.25N,V_(2)=30ml,N_(2)=0.2N`
`thereforeN=(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))=(20(0.25)+30(0.2))/(20+30)`
`=(5+6)/(50)=(11)/(50)=0.2N` basic.


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