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If 2000kg of water is heated from `0^(@)`C to `100^(@)C` , what will be the corresponding increase in mass of water? Take specific heat of water `=1cal. g^(-1).^(@)C^(-1)` . |
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Answer» Here, `m=2000 kg = 2xx10^(6)g, Delta T = 100-0=100^(@)C, c = 1 cal. g^(-1).^(@)C^(-1)`. `:.` Heat energy supplied `//`gained by water, `DeltaW=E=2xx10^(8)xx4.2J=8.4xx10^(8)J.` Hence, increase in mass , `Deltam=(E)/(c^(2))=(8.4xx10^(8))/((3xx10^(8)))=9.3xx10^(-9)kg` |
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