1.

If 22.4 ml of a triatomic gas has a mass of 0.048 gat 273K and 1 atm pressure, then the mass of one atom is:

Answer»

`7.9 xx 10^(-23) g `
`2.6 xx 10^(-23) g `
`2.4 xx 10^(-22) g `
`2.4 xx 10^(-23) g `

Solution :22400 ml of gas weight
` = (0.048)/(22.4) xx 22400 = 48 g `
` therefore ` 1 MOL of gas = 48 g
Mass of ONE atom
`= (48)/(3 xx 6.02 xx 10^23) = 2.6 xx 10^(-23) g `


Discussion

No Comment Found

Related InterviewSolutions