1.

If 224 ml of a triatomic gas has a mass of 1 g at N.T.P., then the mass of one atom is :

Answer»

`9.3 xx 10^(-23) G `
`2.08 xx 10^(-23) g`
`5.53 xx 10^(-23) g `
`9.62 xx 10^(-23) g `

Solution :224 ml of gas weigh = 1g
22400 ml of gas weigh
` = (1)/(224) xx 22400= 100 g `
` THEREFORE ` molecular mass of gas= 100
mass of one molecule ` = (100)/(6.02 xx 10^23)`
mass of atom ` = (100)/(6.02 xx 10^23) xx 1/3 ` (triatomic gas)
= `5.53 xx 10^(-23) g `


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