InterviewSolution
`NP-(PI)/4,npi+TAN^(-1)(1/2), n INZ``npi+(pi)/4, n pi +tan^(-1)(1/2), ninZ``npi-(pi)/4, npi-tan^(-1)(1/2), ninZ``npi+(pi)/4, n pi-tan^(-1)(1/2),n in Z`
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