If `2x^2+lambdax y^+2y^2+(lambda-4)x+6y-5=0,`is the equation of a circ – InterviewSolution

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1.	If `2x^2+lambdax y^+2y^2+(lambda-4)x+6y-5=0,`is the equation of a circle, then its radius is :
Answer» `2x^2+lambdaxy+2y^2+(lambda-4)x+6y-5=0` `x^2+lambda/2xy+y^2+(lambda-4)/2x+3y-5/2=0` `lambda/2=0,lambda=0` `x^2+0+y^2-2x+3y-5/2=0` `C(1,-3/2)` `r=sqrt(1+5/4+5/2)` `r=sqrt((4+9+10)/4)` `r=sqrt23/2`.

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