If √2x + √3y = √5, prove that 2√2x3 + 3√3y3 - 5√5 +3√30

1.	If √2x + √3y = √5, prove that 2√2x3 + 3√3y3 - 5√5 +3√30 xy = 0.
Answer» √2x + √3y = √5 => √2x + √3y - √5 = 0 (if a+b+c = 0, then a³+b³+c³ = 3ABC) => (√2x)³ + (√3y)³ - (√5)³ = 3(√2x)(√3y)(√5) => 2√2x³ + 3√3y³ - 5√5 = 3√30.xy => 2√2x³ + 3√3y³ - 5√5 - 3√30.xy = 0 Therefore, it is proved *hope it HELPS :)*

If √2x + √3y = √5, prove that 2√2x3 + 3√3y3 - 5√5 +3√30 xy = 0.

Answer»

√2x + √3y = √5

=> √2x + √3y - √5 = 0 (if a+b+c = 0, then a³+b³+c³ = 3ABC)

=> (√2x)³ + (√3y)³ - (√5)³ = 3(√2x)(√3y)(√5)

=> 2√2x³ + 3√3y³ - 5√5 = 3√30.xy

=> 2√2x³ + 3√3y³ - 5√5 - 3√30.xy = 0

Therefore, it is proved

hope it HELPS :)

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If √2x + √3y = √5, prove that 2√2x3 + 3√3y3 - 5√5 +3√30 xy = 0.​

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If √2x + √3y = √5, prove that 2√2x3 + 3√3y3 - 5√5 +3√30 xy = 0.