1.

If 3.01 xx 10^(28) molecules are removed from 98 mg of H_2SO_4, then number of moles of H_2SO_4 left are

Answer»

`0.5 xx 10^(-3)` MOL
`0.1 xx 10^(-3)` mol
`9.95 xx 10^(-2)` mol
`1.66 xx 10^(-3)` mol

Solution :`"No. of MOLES" H_(2)SO_(4) "in" 98 mg=(98 xx 10^(-3))/(98)`
`=1 xx 10^(-3)`
No. of moles of `3.01 xx 10^(20)` molecules of `H_(2)SO_(4)`
`=(3.01 xx 10^(20))/(6.02 xx 10^(23))=(1)/(2) xx 10^(-3)`
`"Moles of" H_(2)SO_(4) "left"=(1 xx 10^(-3)-0.5 xx 10^(-3))`
`=0.5 xx 10^(-3)`


Discussion

No Comment Found

Related InterviewSolutions