1.

If 3/4 quantity of a radioactive element disintegrates in two hours, its half-life would be

Answer»

1 hours
45 minutes
30 minutes
15 minutes

Solution :`N = (25)/(100) N_(0)` (at t = 2 HR)
Thus `t = (2.303)/(0.693) XX t_(1//2) "log"(N_(0))/(N)`


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