1.

If 3 sin x + 4 cos x = 5, then 4 sin x – 3 cos x = A. 0 B. 5 C. 1 D. None of these

Answer»

3sin(x) + 4cos(x) = 5

\(\frac{3}5\) sin x + \(\frac{4}5\) cos x = 1

cos(37°- x) = cos 0° (∵ x = 37°)

4sin(x) - 3cos(x) = k

\(4\times\frac{3}5-3\times\frac{4}5\) = 0



Discussion

No Comment Found