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If 3 sin x + 4 cos x = 5, then 4 sin x – 3 cos x = A. 0 B. 5 C. 1 D. None of these |
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Answer» 3sin(x) + 4cos(x) = 5 \(\frac{3}5\) sin x + \(\frac{4}5\) cos x = 1 cos(37°- x) = cos 0° (∵ x = 37°) 4sin(x) - 3cos(x) = k \(4\times\frac{3}5-3\times\frac{4}5\) = 0 |
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