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If 3 tan α = 4 ,and 2 SEᑕ α = 3 k+ 1 ,then find k if α is acute . |
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Answer» Step-by-step explanation: 3 tanα=4 tanα= 4/3 secα= 3k+1 We KNOW that sec²-tan²=1 so, (3k+1)²-(4/3)²=1 (3k+1)²= 1+(4/3)² (3k+1)²= 1+16/9 (3k+1)²= 25/9 on taking root both SIDE we GET 3k+1= ±5/3 3k+1= 5/3 3k= 5/3-1 3k= 2/3 k= 2/9 3k+1= -5/3 3k= -5/3-1 3k= -8/3 k= -8/9
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