1.

If 30 ml of H_(2) and 20 ml of O_(2) react to form water, what is left at the end of the reaction?

Answer»

`"10 ML of "H_(2)`
`"5 ml of "H_(2)`
`"10 ml of "O_(2)`
`"5 ml of "O_(2)`

Solution :`UNDERSET("2 ml")(2H_(2))+underset("1 ml")(O_(2))rarr2H_(2)O`
`"2 ml of "H_(2)" REACT with 1 ml of "O_(2)." Hence, 30 ml of "H_(2)" will react with 15 ml of "O_(2)`


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