1.

If 30 ml of H_(2) and 20ml of O_(2) reacts to form water, what is left at the end of the reaction

Answer»

10 ml of `H_(2)`
5 ml of `H_(2)`
10 ml of `O_(2)`
5 ml of `O_(2)`

Solution :`H_(2)+(1)/(2)O_(2)toH_(2)O`
1 mole `(1)/(2)` mole 1 mole
1 VOLUME `(1)/(2)` volume
1 ml `H_(2)` REACTS with `(1)/(2)`ml `O_(2)`
30 ml of `H_(2)` reacts with `=(1)/(2)xx30=15ml" "O_(2)`
(20-15)=50ml of `O_(2)` will left at the end of the reaction.


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