1.

If 30 ml of H_2and 20 ml of O_2react to formwater, what is left at the end of the reaction ?

Answer»

10 ml of `H_2`
5 ml of `H_2`
10 ml of `O_2`
5 ml of `O_2`

Solution :`underset("2vol")(2H_2) + underset("1 vol")(O_2) to 3H_2O`
2 vol. of `H_2` react with 1 vol of `O_2` to give WATER
` therefore ` 30 ml of `H_2` will react with 15 ml of `O_2`
Hence of `H_2` is a limiting REACTANT
vol of `O_2` left unreacted = 20 - 15 = 5 ml


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