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| 1. |
if 300 g oleum has 60g so3 find %labelling of oleum |
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Answer» in 300g sample has 60gm SO3. so for 100gm , so3 will be (60/300)*(100) = 20gm therefore the labelling % of oleum will be ( 100+20) % = 120% this is the standard formula |
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