1.

If 30g of a solute of molecular weight 154 is dissolved in 250 g of benzene. What will be the elevation in boiling point - (Given : K_(b(C_(e)H_(6))) = 2.6 K Kg mol^(-1))

Answer»

`3.05`
`2.05`
`4.05`
`10`

SOLUTION :`DeltaT_(b)=(K_(b) xx w xx 1000)/(W xx "mol.wt")`
`DeltaT_(b) = (2.6 xx 30 xx 1000)/(250 xx 154)`
`DeltaT_(b) = (78 xx 4)/(154) = 2.05`


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