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If `(3a+5b):(3a-5b): :(3c+5d):(3c-5d)`, then show that a,b,c and d are in proportion. |
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Answer» Given `(3a+5b)/(3a-5b)=(3c+5d)/(3c-5d)` ltbRgt Using componendo and dividendo rule `implies((3a+5b)+(3a-5b))/((3a+5b)-(3a-5b))=((3c+5d)+(3c-5d))/((3c+5d)-(3c-5d))` `implies(6a)/(10b)=(6c)/(10d)implies(a)/(b)=(c)/(d)` `thereforea,b,c and d` are in proportion. |
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