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If = 3l=5 is a multipled of 3 where 2 that is digit what might be the value of z? |
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Answer» Since 31Z5 is a MULTIPLE of 3 ,the SUM of its digits MUST be a multiple of 3 i.e. 3+1+z+5=9+z.Hence 9+z is a multiple of 3Since z is a single digit which can value from 0−9,Possible values of z will be,9+0=99+3=129+6=159+9=18Thus, there can be four possible values i.e. 0,3,6 or 9 |
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