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If 4^3a-1 ÷64=16,find the value of a |
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Answer» Answer: 64= 4^3; 16= 4^2; So, 4^(3a-1)= 64* 16 => 4^(3a-1)= 4^5; (Laws of exponents) Since the BASES are same, 3a- 1= 5 => 3a= 6 => a= 2 (ans.) HOPE IT HELPS!! PLS MARK ME BRAINLIEST!! |
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