1.

If 4.5 gm Aluminium completely reacts with 4gm of oxygen. Then what will be empirical formula of aluminium oxide.

Answer»

`Al_(2)O`
`Al_(2)O_(3)`
`AlO_(2)`
`AIO`

SOLUTION :`Al+O_(2)rarrAl_(X)O_(y)`
`n_(Al)=(4.5)/(27)=(1)/(6) n_(o_(2))=(4)/(52)=(1)/(8)(n_(Al))/(n_(o))=(1)/(6)xx(4)/(1)=(2)/(3)`
`n_(o)=2xxn_(o_(2))=(1)/(4) "FORMULA"=Al_(2)O_(3)`


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