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If `5 cot theta = 3 ," find the value of "((5sin theta - 3 cos theta )/(4 sin theta + 3 cos theta)).` |
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Answer» `5 cot theta =3implies cot theta =(3)/(5) .` Given expression `=((5sin theta - 3 cos theta )/(4 sin theta+3cos theta ))=((5-3 cot theta))/((4+ 3 cot theta ))` `["dividing num.and denom, by "sin theta ]` `=((5-3xx(3)/(5)))/((4+3xx(3)/(5)))=((5-(9)/(5)))/((4+(9)/(5)))=((16)/(5)xx(5)/(29))=(16)/(29).` |
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