If 5 tan^2 a - 5 sec a - 1 = 0Find5 tan a - cot a

1.	If 5 tan^2 a - 5 sec a - 1 = 0Find5 tan a - cot a
Answer» ANSWER: GIVEN that, $5 { \tan }^{2} a - 5 \sec \: a - 1 \\ \\ { \tan }^{2} a - \sec \: a = \frac{1}{5} \\ { \tan }^{2} a = \frac{1}{5} + \frac{1}{ \cos \: a } \\ tana = \sqrt{ \frac{\cos \: a + 5}{5\cos \: a } }$ THEREFORE, $5tana - cota =5 \sqrt{ \frac{5 +\cos \: a }{5\cos \: a } } - \sqrt{ \frac{5\cos \: a }{5 +\cos \: a } }$ this is your answer HOPE it HELPS to you☺️

Answer»

$5 { \tan }^{2} a - 5 \sec \: a - 1 \\ \\ { \tan }^{2} a - \sec \: a = \frac{1}{5} \\ { \tan }^{2} a = \frac{1}{5} + \frac{1}{ \cos \: a } \\ tana = \sqrt{ \frac{\cos \: a + 5}{5\cos \: a } }$

THEREFORE,

$5tana - cota =5 \sqrt{ \frac{5 +\cos \: a }{5\cos \: a } } - \sqrt{ \frac{5\cos \: a }{5 +\cos \: a } }$

this is your answer HOPE it HELPS to you☺️

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If 5 tan^2 a - 5 sec a - 1 = 0Find5 tan a - cot a

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