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If 50% of CO_(2) converts to CO at the following equilibrium : 1/2C(s) + 1/2 CO_(2)(g) hArr CO(g) and the equilibrium pressure is 12 atm Calculate K_(P). |
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Answer» `4` `{:("Initial mole",1/2,0),("Eq"^(n),1/2-1/2x,x):}` `n_("total") = 0.25 + 0.5 = 0.75` `K_(P) = (P_(CO))/(P_(CO_(2))^(1//2)) = ((0.5)/(0.75)xx12)/(SQRT((0.25/(0.075)) xx 12)` `K_(p)= (0.5 xx 12)/(0.75 xx 2) = 2/3 xx 6 = 4` |
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